Basic Plot y = 2x 1 from x = 1 to x = 2 Plot y = x^2 from x = 3 to x = 3 Plot x^2 y^2 = 4 from x = 2 to x = 2 Plot y = sin (x) from x = 0 to x = 2 pi Advanced Plot y = 3x^2 1 and y = 2x^3 4 from x = 3 to x = 3, y = 17 to y = 17 with an aspect ratio of 1 2Plot 3x^22xyy^2=1 WolframAlpha Assuming "plot" is a plotting function Use as referring to geometry instead2) If the equation xy = 2x 2y c, the graph crosses the yaxis at (c/2)
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X^2+xy+y^2=1 graph-Graph the relation and state its domain and range x=y^21 Since y is not in a denominator and y is not in a radical, y can take any value So, Range is All Real NumbersStandard Equation of a Circle The standard, or general, form requires a bit more work than the centerradius form to derive and graph The standard form equation looks like this x2 y2 Dx Ey F = 0 x 2 y 2 D x E y F = 0 In the general form, D D, E E, and F F are given values, like integers, that are coefficients of the x x and
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Explanation This is the equation of a circle with its centre at the origin Think of the axis as the sides of a triangle with the Hypotenuse being the line from the centre to the point on the circle By using Pythagoras you would end up with the equation given where the 4 is in fact r2 To obtain the plot points manipulate the equation as below Given x2 y2 = r2 → x2 y2 = 4 Its graph is shown below From the side view, it appears that the minimum value of this function is around 500 A level curve of a function f (x,y) is a set of points (x,y) in the plane such that f (x,y)=c for a fixed value c Example 5 The level curves of f (x,y) = x 2 y 2 are curves of the form x 2 y 2 =c for different choices of cGraph x^2y^2=1 x2 − y2 = −1 x 2 y 2 = 1 Find the standard form of the hyperbola Tap for more steps Flip the sign on each term of the equation so the term on the right side is positive − x 2 y 2 = 1 x 2 y 2 = 1 Simplify each term in the equation in order to set the right side equal to 1 1 The standard form of an
Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history It looks like this graph{x^2 10, 10, 5, 5} y=x^22 is a parabola shifted/transated two units upwards since 2 is being added to the whole equation The vertex is at (0,2) now graph{x^22 10, 10, 5, 5} You can always plug in values to plot if you'e unsure about the rules of transformations, but they are summarized belowQuestion 3094 graph y 2 = 1/4(x 2) I know this is the pointslope equation, so I know the slope is 1/4, but uncertain how to determine what points to plot on a graph Please help me create the graph Found 2 solutions by Alan3354, stanbon
2x−3y=1 cos (x^2)=y (x−3) (x3)=y^2 y=x^2 If you don't include an equals sign, it will assume you mean " =0 " It has not been well tested, so have fun with it, but don't trust it If it gives you problems, let me know Note it may take a few seconds to finish, because it has to do lots of calculations If you just want to graph a function in "y="Circle on a Graph Let us put a circle of radius 5 on a graph Now let's work out exactly where all the points are We make a rightangled triangle And then use Pythagoras x 2 y 2 = 5 2 There are an infinite number of those points, here are some examplesCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history
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Answer to Consider the hyperbola with equation x^2 y^2 = 1 a Graph the hyperbola There are two points on this curve where x =\sqrt 3Unlock StepbyStep plot x^2y^2x Extended Keyboard ExamplesGraph y=x^21 y = x2 − 1 y = x 2 1 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 − 1 x 2 1 Tap for more steps Use the form a x 2 b x c
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Here is the graph of the surface and we've tried to show the region in the \(xy\)plane below the surface Here is a sketch of the region in the \(xy\)plane by itself By setting the two bounding equations equal we can see that they will intersect at \(x = 2\) and \(x = 2\) It is the equation of a circle Probably you can recognize it as the equation of a circle with radius r=1 and center at the origin, (0,0) The general equation of the circle of radius r and center at (h,k) is (xh)^2(yk)^2=r^2Since the given formula for a circle is x2y2 =1 x 2 y 2 = 1 we can see that the center will be at (0,0) ( 0, 0) and the radius will be See full answer below
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It's the equation of sphere The general equation of sphere looks like math(xx_0)^2(yy_0)^2(zz_0)^2=a^2/math Wheremath (x_0,y_0,z_0)/math is the centre of the circle and matha /math is the radious of the circle It's graph looksYou can clickanddrag to move the graph around If you just clickandrelease (without moving), then the spot you clicked on will be the new center To reset the zoom to the original click on the Reset button Using "a" Values There is a slider with "a =" on it You can use "a" in your formula and then use the slider to change the value of "aWhat I usually do is break a threedimensional graph up into three separate planes, XY, XZ, YZ, and I draw them individually and try to visualize how they fit together
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Graph the ellipse and its foci x^2/9 y^2/4=1 standard forms of ellipse (xh)^2/a^2(yk)^2/b^2=1 (horizontal major axis),a>b (yk)^2/a^2(xh)^2/b^2=1 (vertical major axis),a>b given ellipse has horizontal major axis center(0,0) a^2=9 a=3 b^2=4 b=2 c=sqrt(a^2b^2)=sqrt(94)=sqrt(5)=224 foci=(224,0),(224,0) see graph of givenUse the distributive property to multiply y by x 2 1 Add x to both sides Add x to both sides All equations of the form ax^ {2}bxc=0 can be solved using the quadratic formula \frac {b±\sqrt {b^ {2}4ac}} {2a} The quadratic formula gives two solutions,Graph the parent quadratic (y = x^2) by creating a table of values using select x values The graph of this parent quadratic is called a parabolaNOTE Any
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Graph x^2y^2=1 x2 y2 = 1 x 2 y 2 = 1 This is the form of a circle Use this form to determine the center and radius of the circle (x−h)2 (y−k)2 = r2 ( x h) 2 ( y k) 2 = r 2 Match the values in this circle to those of the standard form The variable r r represents the radius of the circle, h h represents the xoffset from the origin, and k k represents the yoffset from originGraph the parabola, y =x^21 by finding the turning point and using a table to find values for x and yJust as we can write the equation for an ellipse given its graph, we can graph an ellipse given its equation To graph ellipses centered at the origin, we use the standard form x 2 a 2 y 2 b 2 = 1, a > b x 2 a 2 y 2 b 2 = 1, a > b for horizontal ellipses and x 2 b 2 y 2 a 2 = 1, a > b x 2 b 2 y 2 a 2 = 1, a > b for vertical ellipses
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Answer by stanbon (757) ( Show Source ) You can put this solution on YOUR website!A quadratic function in the form f (x) = ax2 bxx f ( x) = a x 2 b x x is in standard form Regardless of the format, the graph of a quadratic function is a parabola The graph of y=x2−4x3 y = x 2 − 4 x 3 The graph of any quadratic equation is always a parabolaThe graph of xy = 2x 2y 1 is shown in gold and crosses the yaxis at 5 The graph of the equation xy = 2x 2y 3 crosses the yaxis at 15 Once again, we may generalize 1) The graph of xy = 2x 2y is a hyperbola asymptotic to y = 2 and x = 2;
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All absolute value graphs look like a "V", the very point that the two lines meet will always be where "y" equals "0" ( since "0" is neither positive or negative, it doesn't have absolute value ), the "V" goes out from this point Let us graph a few pointsAnswer to Consider the hyperbola with equation x^2 y^2 = 1 A) Graph the hyperbola There are two points on this curve where x = sqrt(3) FindExample of how to graph the inverse function y = 1/x by selecting x values and finding corresponding y values
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x^2 y^2 == 1 x^2y^2=1 It is a hyperbola, WolframAlpha is verry helpfull for first findings, The Documentation Center (hit F1) is helpfull as well, see Function Visualization, Plot3D x^2 y^2 == 1, {x, 5, 5}, {y, 5, 5} ContourPlot3D x^2 y^2 == 1, {x, 5, 5}, {y, 5, 5}, {z, 5, 5}Please Subscribe here, thank you!!!//googl/JQ8NysThe Graphs of y = 1/x and y = 1/x^2 College Algebra
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Plot z=x^2y^2 WolframAlpha Assuming "plot" is a plotting function Use as referring to geometry insteadCurves in R2 Graphs vs Level Sets Graphs (y= f(x)) The graph of f R !R is f(x;y) 2R2 jy= f(x)g Example When we say \the curve y= x2," we really mean \The graph of the function f(x) = x2"That is, we mean the set f(x;y) 2R2 jy= x2g Level Sets (F(x;y) = c) The level set of F R2!R at height cis f(x;y) 2R2 jF(x;y) = cg Example When we say \the curve x 2 y = 1," we really mean \The All of the following graphs have the same size and shape as the above curve I am just moving that curve around to show you how it works Example 2 y = x 2 − 2 The only difference with the first graph that I drew (y = x 2) and this one (y = x 2 − 2) is the "minus 2" The "minus 2" means that all the yvalues for the graph need to be moved
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The square of the distance between an input and the point of the graph it corresponds to Show answer When the point is far from the origin, the function will look like , which is nearly zero This means the distance between the graph and the plane at those points will be tinyPrecalculus Graph x^2 (y1)^2=1 x2 (y − 1)2 = 1 x 2 ( y 1) 2 = 1 This is the form of a circle Use this form to determine the center and radius of the circle (x−h)2 (y−k)2 = r2 ( x h) 2 ( y k) 2 = r 2 Match the values in this circle to those of the standard formAssuming you're only working with real numbers Rearange to get that mathx^2y^2=0^2/math This is a circle of radius math0 /math cenetered the orgin But if our circle is of radius math0/math and at the origin, that must mean one thin
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Plane z = 1 The trace in the z = 1 plane is the ellipse x2 y2 8 = 1(e) Below is the graph of z = x2 y2 On the graph of the surface, sketch the traces that you found in parts (a) and (c) For problems 1213, nd an equation of the trace of the surface in the indicated plane Describe the graph of the trace 12 Surface 8x 2 y z2 = 9;A sphere is the graph of an equation of the form x 2 y 2 z 2 = p 2 for some real number p The radius of the sphere is p (see the figure below) Ellipsoids are the graphs of equations of the form ax 2 by 2 cz 2 = p 2, where a, b, and c are all positive
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Graph x=y^22y1 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabolaThis tool graphs z = f (x,y) mathematical functions in 3D It is more of a tour than a tool All functions can be set different boundaries for x, y, and z, to maximize your viewing enjoyment This tool looks really great with a very high detail level, but you may find it more comfortable to use less detail if you want to spin the modelSteps to graph x^2 y^2 = 4
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2 Here is an idea plot the solutions in space, and use a hue determined by, also varying the brightness to convey the orientation of the surface Alternatively, use the cylinder, let again correspond to hue, and let correspond to brightness or saturation There are other ways of doing this too of course, the idea is that you can pack one, two
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